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(8x^2+3)/x^2=0
Domain of the equation: x^2!=0We multiply all the terms by the denominator
x^2!=0/
x^2!=√0
x!=0
x∈R
(8x^2+3)=0
We get rid of parentheses
8x^2+3=0
a = 8; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·8·3
Δ = -96
Delta is less than zero, so there is no solution for the equation
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